import socket
import sys
import netrc
+import xml.etree.ElementTree
from ..utils import (
compat_http_client,
* acodec Name of the audio codec in use
* vbr Average video bitrate in KBit/s
* vcodec Name of the video codec in use
+ * filesize The number of bytes, if known in advance
webpage_url: The url to the video webpage, if given to youtube-dl it
should allow to get the same result again. (It will be set
by YoutubeDL if it's missing)
""" Returns the data of the page as a string """
return self._download_webpage_handle(url_or_request, video_id, note, errnote)[0]
+ def _download_xml(self, url_or_request, video_id, note=u'Downloading XML', errnote=u'Unable to downloand XML'):
+ """Return the xml as an xml.etree.ElementTree.Element"""
+ xml_string = self._download_webpage(url_or_request, video_id, note, errnote)
+ return xml.etree.ElementTree.fromstring(xml_string.encode('utf-8'))
+
def to_screen(self, msg):
"""Print msg to screen, prefixing it with '[ie_name]'"""
self._downloader.to_screen(u'[%s] %s' % (self.IE_NAME, msg))
self.to_screen(u'Logging in')
#Methods for following #608
- def url_result(self, url, ie=None):
+ def url_result(self, url, ie=None, video_id=None):
"""Returns a url that points to a page that should be processed"""
#TODO: ie should be the class used for getting the info
video_info = {'_type': 'url',
'url': url,
'ie_key': ie}
+ if video_id is not None:
+ video_info['id'] = video_id
return video_info
def playlist_result(self, entries, playlist_id=None, playlist_title=None):
"""Returns a playlist"""